Base | Representation |
---|---|
bin | 1100000010111101100110… |
… | …1000101110011010111101 |
3 | 1201220012202022000221000012 |
4 | 3000233121220232122331 |
5 | 3214001313042132331 |
6 | 44100404005513005 |
7 | 2534631220131653 |
oct | 300573150563275 |
9 | 51805668027005 |
10 | 13245035505341 |
11 | 42472082776a2 |
12 | 159ab87712765 |
13 | 75100336a4b3 |
14 | 33b0c5378dd3 |
15 | 17e80170e82b |
hex | c0bd9a2e6bd |
13245035505341 has 4 divisors (see below), whose sum is σ = 13245873655392. Its totient is φ = 13244197355292.
The previous prime is 13245035505323. The next prime is 13245035505371. The reversal of 13245035505341 is 14350553054231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13245035505341 - 214 = 13245035488957 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13245035505371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 419051321 + ... + 419082926.
It is an arithmetic number, because the mean of its divisors is an integer number (3311468413848).
Almost surely, 213245035505341 is an apocalyptic number.
It is an amenable number.
13245035505341 is a deficient number, since it is larger than the sum of its proper divisors (838150051).
13245035505341 is an equidigital number, since it uses as much as digits as its factorization.
13245035505341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 838150050.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 13245035505341 its reverse (14350553054231), we get a palindrome (27595588559572).
The spelling of 13245035505341 in words is "thirteen trillion, two hundred forty-five billion, thirty-five million, five hundred five thousand, three hundred forty-one".
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