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13245035505341 = 15803838134247
BaseRepresentation
bin1100000010111101100110…
…1000101110011010111101
31201220012202022000221000012
43000233121220232122331
53214001313042132331
644100404005513005
72534631220131653
oct300573150563275
951805668027005
1013245035505341
1142472082776a2
12159ab87712765
1375100336a4b3
1433b0c5378dd3
1517e80170e82b
hexc0bd9a2e6bd

13245035505341 has 4 divisors (see below), whose sum is σ = 13245873655392. Its totient is φ = 13244197355292.

The previous prime is 13245035505323. The next prime is 13245035505371. The reversal of 13245035505341 is 14350553054231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13245035505341 - 214 = 13245035488957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13245035505371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 419051321 + ... + 419082926.

It is an arithmetic number, because the mean of its divisors is an integer number (3311468413848).

Almost surely, 213245035505341 is an apocalyptic number.

It is an amenable number.

13245035505341 is a deficient number, since it is larger than the sum of its proper divisors (838150051).

13245035505341 is an equidigital number, since it uses as much as digits as its factorization.

13245035505341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 838150050.

The product of its (nonzero) digits is 540000, while the sum is 41.

Adding to 13245035505341 its reverse (14350553054231), we get a palindrome (27595588559572).

The spelling of 13245035505341 in words is "thirteen trillion, two hundred forty-five billion, thirty-five million, five hundred five thousand, three hundred forty-one".

Divisors: 1 15803 838134247 13245035505341