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132455501335 = 559344673019
BaseRepresentation
bin111101101011011110…
…1101000111000010111
3110122220001101122012201
41323112331220320113
54132232102020320
6140503233025331
712366241120243
oct1732675507027
9418801348181
10132455501335
11511a074a683
12218070b5247
13c64b8238c1
1465a7655423
1536a36ee70a
hex1ed6f68e17

132455501335 has 8 divisors (see below), whose sum is σ = 159214643280. Its totient is φ = 105785706624.

The previous prime is 132455501329. The next prime is 132455501357. The reversal of 132455501335 is 533105554231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132455501335 - 221 = 132453404183 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132455501294 and 132455501303.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22333545 + ... + 22339474.

It is an arithmetic number, because the mean of its divisors is an integer number (19901830410).

Almost surely, 2132455501335 is an apocalyptic number.

132455501335 is a deficient number, since it is larger than the sum of its proper divisors (26759141945).

132455501335 is an equidigital number, since it uses as much as digits as its factorization.

132455501335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44673617.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 132455501335 in words is "one hundred thirty-two billion, four hundred fifty-five million, five hundred one thousand, three hundred thirty-five".

Divisors: 1 5 593 2965 44673019 223365095 26491100267 132455501335