Base | Representation |
---|---|
bin | 1100000010111111100001… |
… | …1000011000010100111010 |
3 | 1201220021002020121201210021 |
4 | 3000233320120120110322 |
5 | 3214003342114023414 |
6 | 44100531113241054 |
7 | 2534650052340661 |
oct | 300577030302472 |
9 | 51807066551707 |
10 | 13245551314234 |
11 | 4247452451538 |
12 | 159b0b040318a |
13 | 751086199165 |
14 | 33b133a87dd8 |
15 | 17e831b4bc24 |
hex | c0bf861853a |
13245551314234 has 4 divisors (see below), whose sum is σ = 19868326971354. Its totient is φ = 6622775657116.
The previous prime is 13245551314201. The next prime is 13245551314327. The reversal of 13245551314234 is 43241315554231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10862396514225 + 2383154800009 = 3295815^2 + 1543747^2 .
It is a super-2 number, since 2×132455513142342 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3311387828557 + ... + 3311387828560.
Almost surely, 213245551314234 is an apocalyptic number.
13245551314234 is a deficient number, since it is larger than the sum of its proper divisors (6622775657120).
13245551314234 is an equidigital number, since it uses as much as digits as its factorization.
13245551314234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6622775657119.
The product of its digits is 864000, while the sum is 43.
Adding to 13245551314234 its reverse (43241315554231), we get a palindrome (56486866868465).
The spelling of 13245551314234 in words is "thirteen trillion, two hundred forty-five billion, five hundred fifty-one million, three hundred fourteen thousand, two hundred thirty-four".
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