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132481173103115 = 526496234620623
BaseRepresentation
bin11110000111110110101101…
…010000110010001000001011
3122101002002001201221101200012
4132013312231100302020023
5114331032420303244430
61145433002152302135
736622306654125044
oct3607665520621013
9571062051841605
10132481173103115
1139237a4a4921a1
1212a378a49a194b
1358bcbc8627445
1424a01a16b78cb
15104b215414695
hex787dad43220b

132481173103115 has 4 divisors (see below), whose sum is σ = 158977407723744. Its totient is φ = 105984938482488.

The previous prime is 132481173103087. The next prime is 132481173103133. The reversal of 132481173103115 is 511301371184231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132481173103115 - 234 = 132463993233931 is a prime.

It is a super-2 number, since 2×1324811731031152 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13248117310307 + ... + 13248117310316.

It is an arithmetic number, because the mean of its divisors is an integer number (39744351930936).

Almost surely, 2132481173103115 is an apocalyptic number.

132481173103115 is a deficient number, since it is larger than the sum of its proper divisors (26496234620629).

132481173103115 is an equidigital number, since it uses as much as digits as its factorization.

132481173103115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26496234620628.

The product of its (nonzero) digits is 60480, while the sum is 41.

The spelling of 132481173103115 in words is "one hundred thirty-two trillion, four hundred eighty-one billion, one hundred seventy-three million, one hundred three thousand, one hundred fifteen".

Divisors: 1 5 26496234620623 132481173103115