Base | Representation |
---|---|
bin | 11110000111110110101101… |
… | …010000110010000111101111 |
3 | 122101002002001201221101122011 |
4 | 132013312231100302013233 |
5 | 114331032420303244322 |
6 | 1145433002152302051 |
7 | 36622306654125004 |
oct | 3607665520620757 |
9 | 571062051841564 |
10 | 132481173103087 |
11 | 39237a4a492176 |
12 | 12a378a49a1927 |
13 | 58bcbc8627423 |
14 | 24a01a16b78ab |
15 | 104b215414677 |
hex | 787dad4321ef |
132481173103087 has 2 divisors, whose sum is σ = 132481173103088. Its totient is φ = 132481173103086.
The previous prime is 132481173103003. The next prime is 132481173103133. The reversal of 132481173103087 is 780301371184231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132481173103087 is a prime.
It is a super-2 number, since 2×1324811731030872 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132481173103087.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132481173103987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66240586551543 + 66240586551544.
It is an arithmetic number, because the mean of its divisors is an integer number (66240586551544).
Almost surely, 2132481173103087 is an apocalyptic number.
132481173103087 is a deficient number, since it is larger than the sum of its proper divisors (1).
132481173103087 is an equidigital number, since it uses as much as digits as its factorization.
132481173103087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 677376, while the sum is 49.
The spelling of 132481173103087 in words is "one hundred thirty-two trillion, four hundred eighty-one billion, one hundred seventy-three million, one hundred three thousand, eighty-seven".
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