Base | Representation |
---|---|
bin | 1100000011001101101010… |
… | …1001011100101000000000 |
3 | 1201220121212210200212010200 |
4 | 3000303122221130220000 |
5 | 3214034130421022404 |
6 | 44102355521325200 |
7 | 2535143116020300 |
oct | 300633251345000 |
9 | 51817783625120 |
10 | 13249347439104 |
11 | 4249020246317 |
12 | 159b98b796800 |
13 | 75153c7a77aa |
14 | 33b3b3ccb600 |
15 | 17e9a504e839 |
hex | c0cdaa5ca00 |
13249347439104 has 180 divisors, whose sum is σ = 44481537219834. Its totient is φ = 3785527775232.
The previous prime is 13249347439049. The next prime is 13249347439151. The reversal of 13249347439104 is 40193474394231.
13249347439104 is a `hidden beast` number, since 1 + 3 + 2 + 493 + 4 + 7 + 43 + 9 + 104 = 666.
It can be written as a sum of positive squares in only one way, i.e., 12816972806400 + 432374632704 = 3580080^2 + 657552^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 29113927 + ... + 29565510.
Almost surely, 213249347439104 is an apocalyptic number.
13249347439104 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13249347439104 is an abundant number, since it is smaller than the sum of its proper divisors (31232189780730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13249347439104 is an equidigital number, since it uses as much as digits as its factorization.
13249347439104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58679475 (or 58679449 counting only the distinct ones).
The product of its (nonzero) digits is 7838208, while the sum is 54.
The spelling of 13249347439104 in words is "thirteen trillion, two hundred forty-nine billion, three hundred forty-seven million, four hundred thirty-nine thousand, one hundred four".
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