Base | Representation |
---|---|
bin | 10011010010000000010… |
… | …101100001110010100001 |
3 | 11200200001202000012200010 |
4 | 103102000111201302201 |
5 | 133202101240213431 |
6 | 2452410433515133 |
7 | 164504545063266 |
oct | 23220025416241 |
9 | 4620052005603 |
10 | 1325003054241 |
11 | 470a26754989 |
12 | 194964a12aa9 |
13 | 97c4115cba9 |
14 | 481b80c926d |
15 | 246edeec846 |
hex | 13480561ca1 |
1325003054241 has 8 divisors (see below), whose sum is σ = 1766678524864. Its totient is φ = 883331476560.
The previous prime is 1325003054233. The next prime is 1325003054257. The reversal of 1325003054241 is 1424503005231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1325003054241 - 23 = 1325003054233 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1325003054199 and 1325003054208.
It is not an unprimeable number, because it can be changed into a prime (1325003055241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55405 + ... + 1628826.
It is an arithmetic number, because the mean of its divisors is an integer number (220834815608).
Almost surely, 21325003054241 is an apocalyptic number.
It is an amenable number.
1325003054241 is a deficient number, since it is larger than the sum of its proper divisors (441675470623).
1325003054241 is a wasteful number, since it uses less digits than its factorization.
1325003054241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1946471.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 1325003054241 its reverse (1424503005231), we get a palindrome (2749506059472).
The spelling of 1325003054241 in words is "one trillion, three hundred twenty-five billion, three million, fifty-four thousand, two hundred forty-one".
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