1325006943757 has 4 divisors (see below), whose sum is σ = 1514293650016. Its totient is φ = 1135720237500.

The previous prime is 1325006943749. The next prime is 1325006943761. The reversal of 1325006943757 is 7573496005231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1325006943757 - 2³ = 1325006943749 is a prime.

It is a super-2 number, since 2×1325006943757² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1325006941757) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94643353119 + ... + 94643353132.

It is an arithmetic number, because the mean of its divisors is an integer number (378573412504).

Almost surely, 2^{1325006943757} is an apocalyptic number.

It is an amenable number.

1325006943757 is a deficient number, since it is larger than the sum of its proper divisors (189286706259).

1325006943757 is an equidigital number, since it uses as much as digits as its factorization.

1325006943757 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 189286706258.

The product of its (nonzero) digits is 4762800, while the sum is 52.

The spelling of 1325006943757 in words is "one trillion, three hundred twenty-five billion, six million, nine hundred forty-three thousand, seven hundred fifty-seven".