Base | Representation |
---|---|
bin | 1100000011010000101110… |
… | …1101101110011100001011 |
3 | 1201220201000011201000021121 |
4 | 3000310023231232130023 |
5 | 3214042322141103420 |
6 | 44103013325420111 |
7 | 2535202403112250 |
oct | 300641355563413 |
9 | 51821004630247 |
10 | 13250170644235 |
11 | 4249402996538 |
12 | 159bb7b40a637 |
13 | 7516411c3915 |
14 | 33b451377427 |
15 | 17ea0245c2aa |
hex | c0d0bb6e70b |
13250170644235 has 32 divisors (see below), whose sum is σ = 18270033610752. Its totient is φ = 9036778573440.
The previous prime is 13250170644209. The next prime is 13250170644241. The reversal of 13250170644235 is 53244607105231.
13250170644235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13250170644235 - 225 = 13250137089803 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13250170644191 and 13250170644200.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3408420 + ... + 6173950.
It is an arithmetic number, because the mean of its divisors is an integer number (570938550336).
Almost surely, 213250170644235 is an apocalyptic number.
13250170644235 is a deficient number, since it is larger than the sum of its proper divisors (5019862966517).
13250170644235 is a wasteful number, since it uses less digits than its factorization.
13250170644235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2766283.
The product of its (nonzero) digits is 604800, while the sum is 43.
Adding to 13250170644235 its reverse (53244607105231), we get a palindrome (66494777749466).
The spelling of 13250170644235 in words is "thirteen trillion, two hundred fifty billion, one hundred seventy million, six hundred forty-four thousand, two hundred thirty-five".
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