132502103351041 has 4 divisors (see below), whose sum is σ = 132520133308500. Its totient is φ = 132484073393584.

The previous prime is 132502103350973. The next prime is 132502103351119. The reversal of 132502103351041 is 140153301205231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 90378485697600 + 42123617653441 = 9506760^2 + 6490271^2 .

It is a cyclic number.

It is not a de Polignac number, because 132502103351041 - 2²¹ = 132502101253889 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132502103350994 and 132502103351012.

It is not an unprimeable number, because it can be changed into a prime (132502103351941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9014967706 + ... + 9014982403.

It is an arithmetic number, because the mean of its divisors is an integer number (33130033327125).

Almost surely, 2^{132502103351041} is an apocalyptic number.

It is an amenable number.

132502103351041 is a deficient number, since it is larger than the sum of its proper divisors (18029957459).

132502103351041 is an equidigital number, since it uses as much as digits as its factorization.

132502103351041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18029957458.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 132502103351041 its reverse (140153301205231), we get a palindrome (272655404556272).

The spelling of 132502103351041 in words is "one hundred thirty-two trillion, five hundred two billion, one hundred three million, three hundred fifty-one thousand, forty-one".