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132502103351941 is a prime number
BaseRepresentation
bin11110001000001010001100…
…110011010110001010000101
3122101011002002101220012102011
4132020022030303112022011
5114331403301424230231
61145450343112214221
736623650433243461
oct3610121463261205
9571132071805364
10132502103351941
11392459100239a4
1212a3b96639a371
1358c1b82959a6b
1424a11c93514a1
15104ba3cb849b1
hex78828ccd6285

132502103351941 has 2 divisors, whose sum is σ = 132502103351942. Its totient is φ = 132502103351940.

The previous prime is 132502103351909. The next prime is 132502103351963. The reversal of 132502103351941 is 149153301205231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98517237592225 + 33984865759716 = 9925585^2 + 5829654^2 .

It is a cyclic number.

It is not a de Polignac number, because 132502103351941 - 25 = 132502103351909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132502103351894 and 132502103351903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132502103301941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66251051675970 + 66251051675971.

It is an arithmetic number, because the mean of its divisors is an integer number (66251051675971).

Almost surely, 2132502103351941 is an apocalyptic number.

It is an amenable number.

132502103351941 is a deficient number, since it is larger than the sum of its proper divisors (1).

132502103351941 is an equidigital number, since it uses as much as digits as its factorization.

132502103351941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 40.

The spelling of 132502103351941 in words is "one hundred thirty-two trillion, five hundred two billion, one hundred three million, three hundred fifty-one thousand, nine hundred forty-one".