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132503605004243 = 1112045782273113
BaseRepresentation
bin11110001000001011100110…
…010011101100011111010011
3122101011012222001112001010002
4132020023212103230133103
5114331414340340113433
61145451152114000215
736624032566132514
oct3610134623543723
9571135861461102
10132503605004243
1139246510732560
1212a4010527606b
1358c2061aaa115
1424a12cc964a0b
15104bac99089e8
hex7882e64ec7d3

132503605004243 has 4 divisors (see below), whose sum is σ = 144549387277368. Its totient is φ = 120457822731120.

The previous prime is 132503605004233. The next prime is 132503605004249. The reversal of 132503605004243 is 342400506305231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132503605004243 - 210 = 132503605003219 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132503605004197 and 132503605004206.

It is not an unprimeable number, because it can be changed into a prime (132503605004249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6022891136546 + ... + 6022891136567.

It is an arithmetic number, because the mean of its divisors is an integer number (36137346819342).

Almost surely, 2132503605004243 is an apocalyptic number.

132503605004243 is a deficient number, since it is larger than the sum of its proper divisors (12045782273125).

132503605004243 is a wasteful number, since it uses less digits than its factorization.

132503605004243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12045782273124.

The product of its (nonzero) digits is 259200, while the sum is 38.

The spelling of 132503605004243 in words is "one hundred thirty-two trillion, five hundred three billion, six hundred five million, four thousand, two hundred forty-three".

Divisors: 1 11 12045782273113 132503605004243