13250443533 has 4 divisors (see below), whose sum is σ = 17667258048. Its totient is φ = 8833629020.

The previous prime is 13250443529. The next prime is 13250443541. The reversal of 13250443533 is 33534405231.

13250443533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13250443533 - 2² = 13250443529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13250443494 and 13250443503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13250443513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2208407253 + ... + 2208407258.

It is an arithmetic number, because the mean of its divisors is an integer number (4416814512).

Almost surely, 2^13250443533 is an apocalyptic number.

It is an amenable number.

13250443533 is a deficient number, since it is larger than the sum of its proper divisors (4416814515).

13250443533 is an equidigital number, since it uses as much as digits as its factorization.

13250443533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4416814514.

The product of its (nonzero) digits is 64800, while the sum is 33.

Adding to 13250443533 its reverse (33534405231), we get a palindrome (46784848764).

The spelling of 13250443533 in words is "thirteen billion, two hundred fifty million, four hundred forty-three thousand, five hundred thirty-three".