Base | Representation |
---|---|
bin | 11000101011101011… |
… | …10001110000111111 |
3 | 1021012111200211220210 |
4 | 30111311301300333 |
5 | 204114314232040 |
6 | 10030525443503 |
7 | 646244240421 |
oct | 142565616077 |
9 | 37174624823 |
10 | 13251320895 |
11 | 569003057a |
12 | 2699a10593 |
13 | 13324876a7 |
14 | 8d9caa811 |
15 | 528547480 |
hex | 315d71c3f |
13251320895 has 8 divisors (see below), whose sum is σ = 21202113456. Its totient is φ = 7067371136.
The previous prime is 13251320893. The next prime is 13251320921. The reversal of 13251320895 is 59802315231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13251320895 - 21 = 13251320893 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13251320893) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 441710682 + ... + 441710711.
It is an arithmetic number, because the mean of its divisors is an integer number (2650264182).
Almost surely, 213251320895 is an apocalyptic number.
13251320895 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13251320895 is a deficient number, since it is larger than the sum of its proper divisors (7950792561).
13251320895 is an equidigital number, since it uses as much as digits as its factorization.
13251320895 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 883421401.
The product of its (nonzero) digits is 64800, while the sum is 39.
The spelling of 13251320895 in words is "thirteen billion, two hundred fifty-one million, three hundred twenty thousand, eight hundred ninety-five".
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