Base | Representation |
---|---|
bin | 111101101101011101… |
… | …1011101101011110011 |
3 | 110200001200121011011121 |
4 | 1323122323131223303 |
5 | 4132401120240201 |
6 | 140514011123111 |
7 | 12401006516542 |
oct | 1733273355363 |
9 | 420050534147 |
10 | 132522040051 |
11 | 51225267155 |
12 | 21825443497 |
13 | c65c54cb1b |
14 | 65b2416159 |
15 | 36a94949a1 |
hex | 1edaeddaf3 |
132522040051 has 8 divisors (see below), whose sum is σ = 137098029600. Its totient is φ = 127946468160.
The previous prime is 132522040033. The next prime is 132522040117. The reversal of 132522040051 is 150040225231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132522040051 - 211 = 132522038003 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132522039998 and 132522040025.
It is not an unprimeable number, because it can be changed into a prime (132522040451) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 628410 + ... + 812368.
It is an arithmetic number, because the mean of its divisors is an integer number (17137253700).
Almost surely, 2132522040051 is an apocalyptic number.
132522040051 is a deficient number, since it is larger than the sum of its proper divisors (4575989549).
132522040051 is a wasteful number, since it uses less digits than its factorization.
132522040051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 208829.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 132522040051 its reverse (150040225231), we get a palindrome (282562265282).
The spelling of 132522040051 in words is "one hundred thirty-two billion, five hundred twenty-two million, forty thousand, fifty-one".
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