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132522040051 = 2924841183959
BaseRepresentation
bin111101101101011101…
…1011101101011110011
3110200001200121011011121
41323122323131223303
54132401120240201
6140514011123111
712401006516542
oct1733273355363
9420050534147
10132522040051
1151225267155
1221825443497
13c65c54cb1b
1465b2416159
1536a94949a1
hex1edaeddaf3

132522040051 has 8 divisors (see below), whose sum is σ = 137098029600. Its totient is φ = 127946468160.

The previous prime is 132522040033. The next prime is 132522040117. The reversal of 132522040051 is 150040225231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132522040051 - 211 = 132522038003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132522039998 and 132522040025.

It is not an unprimeable number, because it can be changed into a prime (132522040451) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 628410 + ... + 812368.

It is an arithmetic number, because the mean of its divisors is an integer number (17137253700).

Almost surely, 2132522040051 is an apocalyptic number.

132522040051 is a deficient number, since it is larger than the sum of its proper divisors (4575989549).

132522040051 is a wasteful number, since it uses less digits than its factorization.

132522040051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 208829.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 132522040051 its reverse (150040225231), we get a palindrome (282562265282).

The spelling of 132522040051 in words is "one hundred thirty-two billion, five hundred twenty-two million, forty thousand, fifty-one".

Divisors: 1 29 24841 183959 720389 5334811 4569725519 132522040051