Base | Representation |
---|---|
bin | 11000101011110010… |
… | …01101010010001011 |
3 | 1021012120101112022120 |
4 | 30111321031102023 |
5 | 204120032020133 |
6 | 10031001022323 |
7 | 646255004016 |
oct | 142571152213 |
9 | 37176345276 |
10 | 13252220043 |
11 | 5690595077 |
12 | 269a1849a3 |
13 | 1332710a2a |
14 | 8da06237d |
15 | 528673ab3 |
hex | 315e4d48b |
13252220043 has 16 divisors (see below), whose sum is σ = 17938108416. Its totient is φ = 8700642720.
The previous prime is 13252220029. The next prime is 13252220087. The reversal of 13252220043 is 34002225231.
13252220043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13252220043 - 24 = 13252220027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13252219995 and 13252220022.
It is not an unprimeable number, because it can be changed into a prime (13252220143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1100113 + ... + 1112093.
It is an arithmetic number, because the mean of its divisors is an integer number (1121131776).
Almost surely, 213252220043 is an apocalyptic number.
13252220043 is a deficient number, since it is larger than the sum of its proper divisors (4685888373).
13252220043 is a wasteful number, since it uses less digits than its factorization.
13252220043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17554.
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 13252220043 its reverse (34002225231), we get a palindrome (47254445274).
The spelling of 13252220043 in words is "thirteen billion, two hundred fifty-two million, two hundred twenty thousand, forty-three".
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