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13252254019 = 49992650981
BaseRepresentation
bin11000101011110010…
…10101100101000011
31021012120110020220221
430111321111211003
5204120034112034
610031001443511
7646255205044
oct142571254503
937176406827
1013252254019
115690608654
12269a1a0597
131332723334
148da0708cb
1552867dbb4
hex315e55943

13252254019 has 4 divisors (see below), whose sum is σ = 13254910000. Its totient is φ = 13249598040.

The previous prime is 13252254017. The next prime is 13252254031. The reversal of 13252254019 is 91045225231.

13252254019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13252254019 - 21 = 13252254017 is a prime.

It is a super-2 number, since 2×132522540192 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13252254017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320492 + ... + 1330489.

It is an arithmetic number, because the mean of its divisors is an integer number (3313727500).

Almost surely, 213252254019 is an apocalyptic number.

13252254019 is a deficient number, since it is larger than the sum of its proper divisors (2655981).

13252254019 is an equidigital number, since it uses as much as digits as its factorization.

13252254019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2655980.

The product of its (nonzero) digits is 21600, while the sum is 34.

The spelling of 13252254019 in words is "thirteen billion, two hundred fifty-two million, two hundred fifty-four thousand, nineteen".

Divisors: 1 4999 2650981 13252254019