Base | Representation |
---|---|
bin | 111101101101100101… |
… | …0100111111101110001 |
3 | 110200001222002001211210 |
4 | 1323123022213331301 |
5 | 4132403124424241 |
6 | 140514232230333 |
7 | 12401055351411 |
oct | 1733312477561 |
9 | 420058061753 |
10 | 132526014321 |
11 | 51227531078 |
12 | 2182683b3a9 |
13 | c660311a6c |
14 | 65b2b6c641 |
15 | 36a99cc316 |
hex | 1edb2a7f71 |
132526014321 has 4 divisors (see below), whose sum is σ = 176701352432. Its totient is φ = 88350676212.
The previous prime is 132526014259. The next prime is 132526014323. The reversal of 132526014321 is 123410625231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 132526014321 - 211 = 132526012273 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (132526014323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22087669051 + ... + 22087669056.
It is an arithmetic number, because the mean of its divisors is an integer number (44175338108).
Almost surely, 2132526014321 is an apocalyptic number.
It is an amenable number.
132526014321 is a deficient number, since it is larger than the sum of its proper divisors (44175338111).
132526014321 is an equidigital number, since it uses as much as digits as its factorization.
132526014321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44175338110.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 132526014321 its reverse (123410625231), we get a palindrome (255936639552).
The spelling of 132526014321 in words is "one hundred thirty-two billion, five hundred twenty-six million, fourteen thousand, three hundred twenty-one".
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