Base | Representation |
---|---|
bin | 1100000011011100110001… |
… | …1110000111011101011111 |
3 | 1201221000100112212201000012 |
4 | 3000313030132013131133 |
5 | 3214120433031230403 |
6 | 44104310251353435 |
7 | 2535345501646646 |
oct | 300671436073537 |
9 | 51830315781005 |
10 | 13253404555103 |
11 | 424a8123a0649 |
12 | 15a072245287b |
13 | 751a381a654b |
14 | 33b67aa6c35d |
15 | 17eb41307ed8 |
hex | c0dcc78775f |
13253404555103 has 8 divisors (see below), whose sum is σ = 13256457528480. Its totient is φ = 13250351950560.
The previous prime is 13253404555087. The next prime is 13253404555129. The reversal of 13253404555103 is 30155540435231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13253404555103 - 24 = 13253404555087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13253404555003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79484726 + ... + 79651292.
It is an arithmetic number, because the mean of its divisors is an integer number (1657057191060).
Almost surely, 213253404555103 is an apocalyptic number.
13253404555103 is a deficient number, since it is larger than the sum of its proper divisors (3052973377).
13253404555103 is an equidigital number, since it uses as much as digits as its factorization.
13253404555103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 184417.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 13253404555103 in words is "thirteen trillion, two hundred fifty-three billion, four hundred four million, five hundred fifty-five thousand, one hundred three".
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