Base | Representation |
---|---|
bin | 10011010010011000000… |
… | …000001000110011010111 |
3 | 11200201002102010020010122 |
4 | 103102120000020303113 |
5 | 133203404411200210 |
6 | 2452514055542155 |
7 | 164520435652253 |
oct | 23223000106327 |
9 | 4621072106118 |
10 | 1325400100055 |
11 | 47110a892319 |
12 | 194a5598a95b |
13 | 97ca54a8945 |
14 | 48214b21263 |
15 | 24723ccab55 |
hex | 13498008cd7 |
1325400100055 has 8 divisors (see below), whose sum is σ = 1591532730144. Its totient is φ = 1059618340000.
The previous prime is 1325400100001. The next prime is 1325400100093. The reversal of 1325400100055 is 5500010045231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1325400100055 - 222 = 1325395905751 is a prime.
It is a super-2 number, since 2×13254001000552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1325400099997 and 1325400100033.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87709196 + ... + 87724305.
It is an arithmetic number, because the mean of its divisors is an integer number (198941591268).
Almost surely, 21325400100055 is an apocalyptic number.
1325400100055 is a deficient number, since it is larger than the sum of its proper divisors (266132630089).
1325400100055 is a wasteful number, since it uses less digits than its factorization.
1325400100055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 175435017.
The product of its (nonzero) digits is 3000, while the sum is 26.
Adding to 1325400100055 its reverse (5500010045231), we get a palindrome (6825410145286).
The spelling of 1325400100055 in words is "one trillion, three hundred twenty-five billion, four hundred million, one hundred thousand, fifty-five".
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