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1325405043301 = 2834683410047
BaseRepresentation
bin10011010010011000010…
…010111111101001100101
311200201002202102100222211
4103102120102333221211
5133203412142341201
62452514353523421
7164520525661123
oct23223022775145
94621082370884
101325405043301
11471112659249
12194a57573571
1397ca6519941
144821564a913
1524724455651
hex134984bfa65

1325405043301 has 4 divisors (see below), whose sum is σ = 1330088453632. Its totient is φ = 1320721632972.

The previous prime is 1325405043283. The next prime is 1325405043341. The reversal of 1325405043301 is 1033405045231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1325405043301 - 213 = 1325405035109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1325405043341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2341704741 + ... + 2341705306.

It is an arithmetic number, because the mean of its divisors is an integer number (332522113408).

Almost surely, 21325405043301 is an apocalyptic number.

It is an amenable number.

1325405043301 is a deficient number, since it is larger than the sum of its proper divisors (4683410331).

1325405043301 is an equidigital number, since it uses as much as digits as its factorization.

1325405043301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4683410330.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 1325405043301 in words is "one trillion, three hundred twenty-five billion, four hundred five million, forty-three thousand, three hundred one".

Divisors: 1 283 4683410047 1325405043301