Base | Representation |
---|---|
bin | 1100000011011111100001… |
… | …0100111010111100011001 |
3 | 1201221002020211101112221021 |
4 | 3000313320110322330121 |
5 | 3214123434411421131 |
6 | 44104511254042441 |
7 | 2535402645021244 |
oct | 300677024727431 |
9 | 51832224345837 |
10 | 13254140342041 |
11 | 425005a763225 |
12 | 15a08a8949421 |
13 | 751b24765931 |
14 | 33b70a68025b |
15 | 17eb85be8e11 |
hex | c0df853af19 |
13254140342041 has 4 divisors (see below), whose sum is σ = 13254148718800. Its totient is φ = 13254131965284.
The previous prime is 13254140342011. The next prime is 13254140342083. The reversal of 13254140342041 is 14024304145231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13254140342041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13254140341988 and 13254140342006.
It is not an unprimeable number, because it can be changed into a prime (13254140342011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1012071 + ... + 5247148.
It is an arithmetic number, because the mean of its divisors is an integer number (3313537179700).
Almost surely, 213254140342041 is an apocalyptic number.
It is an amenable number.
13254140342041 is a deficient number, since it is larger than the sum of its proper divisors (8376759).
13254140342041 is an equidigital number, since it uses as much as digits as its factorization.
13254140342041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8376758.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 13254140342041 its reverse (14024304145231), we get a palindrome (27278444487272).
The spelling of 13254140342041 in words is "thirteen trillion, two hundred fifty-four billion, one hundred forty million, three hundred forty-two thousand, forty-one".
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