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1325441412343 = 1537786196359
BaseRepresentation
bin10011010010011010011…
…101101110110011110111
311200201012021212002221101
4103102122131232303313
5133204001000143333
62452522133230531
7164521450054246
oct23223235566367
94621167762841
101325441412343
11471131139904
12194a67792447
1397cb0c11899
144821a3d695d
152472773b67d
hex1349a76ecf7

1325441412343 has 4 divisors (see below), whose sum is σ = 1325527624080. Its totient is φ = 1325355200608.

The previous prime is 1325441412299. The next prime is 1325441412359. The reversal of 1325441412343 is 3432141445231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1325441412343 - 29 = 1325441411831 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1325441412443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43082803 + ... + 43113556.

It is an arithmetic number, because the mean of its divisors is an integer number (331381906020).

Almost surely, 21325441412343 is an apocalyptic number.

1325441412343 is a deficient number, since it is larger than the sum of its proper divisors (86211737).

1325441412343 is an equidigital number, since it uses as much as digits as its factorization.

1325441412343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86211736.

The product of its digits is 138240, while the sum is 37.

Adding to 1325441412343 its reverse (3432141445231), we get a palindrome (4757582857574).

The spelling of 1325441412343 in words is "one trillion, three hundred twenty-five billion, four hundred forty-one million, four hundred twelve thousand, three hundred forty-three".

Divisors: 1 15377 86196359 1325441412343