Base | Representation |
---|---|
bin | 11110001000110111001110… |
… | …001100010000100111001010 |
3 | 122101022200212102022111121211 |
4 | 132020313032030100213022 |
5 | 114333201302412321442 |
6 | 1145524500034323334 |
7 | 36630311410651642 |
oct | 3610671614204712 |
9 | 571280772274554 |
10 | 132550445042122 |
11 | 39264367709268 |
12 | 12a491b7a2954a |
13 | 58c65b7c89173 |
14 | 24a369372d522 |
15 | 104ce1bb5d617 |
hex | 788dce3109ca |
132550445042122 has 4 divisors (see below), whose sum is σ = 198825667563186. Its totient is φ = 66275222521060.
The previous prime is 132550445042063. The next prime is 132550445042129. The reversal of 132550445042122 is 221240544055231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 82914883389121 + 49635561653001 = 9105761^2 + 7045251^2 .
It is not an unprimeable number, because it can be changed into a prime (132550445042129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33137611260529 + ... + 33137611260532.
Almost surely, 2132550445042122 is an apocalyptic number.
132550445042122 is a deficient number, since it is larger than the sum of its proper divisors (66275222521064).
132550445042122 is an equidigital number, since it uses as much as digits as its factorization.
132550445042122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66275222521063.
The product of its (nonzero) digits is 384000, while the sum is 40.
Adding to 132550445042122 its reverse (221240544055231), we get a palindrome (353790989097353).
The spelling of 132550445042122 in words is "one hundred thirty-two trillion, five hundred fifty billion, four hundred forty-five million, forty-two thousand, one hundred twenty-two".
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