1325505126343 has 4 divisors (see below), whose sum is σ = 1327510429768. Its totient is φ = 1323499822920.

The previous prime is 1325505126313. The next prime is 1325505126347. The reversal of 1325505126343 is 3436215055231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1325505126343 - 2³³ = 1316915191751 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1325505126296 and 1325505126305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1325505126347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1002650721 + ... + 1002652042.

It is an arithmetic number, because the mean of its divisors is an integer number (331877607442).

Almost surely, 2^{1325505126343} is an apocalyptic number.

1325505126343 is a deficient number, since it is larger than the sum of its proper divisors (2005303425).

1325505126343 is an equidigital number, since it uses as much as digits as its factorization.

1325505126343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2005303424.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 1325505126343 in words is "one trillion, three hundred twenty-five billion, five hundred five million, one hundred twenty-six thousand, three hundred forty-three".