Base | Representation |
---|---|
bin | 10011010010100000100… |
… | …111001011110001000111 |
3 | 11200201110110221020001211 |
4 | 103102200213023301013 |
5 | 133204203401203133 |
6 | 2452540300032251 |
7 | 164524141541410 |
oct | 23224047136107 |
9 | 4621413836054 |
10 | 1325544553543 |
11 | 471184386371 |
12 | 194a96232687 |
13 | 97cc93b5092 |
14 | 48229da4807 |
15 | 24731811bcd |
hex | 134a09cbc47 |
1325544553543 has 4 divisors (see below), whose sum is σ = 1514908061200. Its totient is φ = 1136181045888.
The previous prime is 1325544553511. The next prime is 1325544553573. The reversal of 1325544553543 is 3453554455231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1325544553543 - 25 = 1325544553511 is a prime.
It is a super-2 number, since 2×13255445535432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1325544553573) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94681753818 + ... + 94681753831.
It is an arithmetic number, because the mean of its divisors is an integer number (378727015300).
Almost surely, 21325544553543 is an apocalyptic number.
1325544553543 is a deficient number, since it is larger than the sum of its proper divisors (189363507657).
1325544553543 is an equidigital number, since it uses as much as digits as its factorization.
1325544553543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 189363507656.
The product of its digits is 10800000, while the sum is 49.
The spelling of 1325544553543 in words is "one trillion, three hundred twenty-five billion, five hundred forty-four million, five hundred fifty-three thousand, five hundred forty-three".
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