Base | Representation |
---|---|
bin | 11000101100110001… |
… | …11100111001011101 |
3 | 1021020011001022020220 |
4 | 30112120330321131 |
5 | 204124144312113 |
6 | 10031455231553 |
7 | 646415512641 |
oct | 142630747135 |
9 | 37204038226 |
10 | 13260541533 |
11 | 5695259138 |
12 | 26a0b185b9 |
13 | 13343655a5 |
14 | 8db1cac21 |
15 | 529269523 |
hex | 31663ce5d |
13260541533 has 8 divisors (see below), whose sum is σ = 17700794496. Its totient is φ = 8830324800.
The previous prime is 13260541531. The next prime is 13260541549. The reversal of 13260541533 is 33514506231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13260541533 - 21 = 13260541531 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13260541494 and 13260541503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13260541531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2505973 + ... + 2511258.
It is an arithmetic number, because the mean of its divisors is an integer number (2212599312).
Almost surely, 213260541533 is an apocalyptic number.
It is an amenable number.
13260541533 is a deficient number, since it is larger than the sum of its proper divisors (4440252963).
13260541533 is an equidigital number, since it uses as much as digits as its factorization.
13260541533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5018115.
The product of its (nonzero) digits is 32400, while the sum is 33.
The spelling of 13260541533 in words is "thirteen billion, two hundred sixty million, five hundred forty-one thousand, five hundred thirty-three".
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