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132656502665503 = 711868401445993
BaseRepresentation
bin11110001010011001111111…
…101101111111000100011111
3122101200211121202102222222001
4132022121333231333010133
5114341421004140244003
61150045320033303131
736641054541614005
oct3612317755770437
9571624552388861
10132656502665503
11392a5341452483
1212a65876404aa7
1359035ba78b92b
1424a88750bca75
151050a77ab461d
hex78a67fb7f11f

132656502665503 has 4 divisors (see below), whose sum is σ = 134524904111568. Its totient is φ = 130788101219440.

The previous prime is 132656502665399. The next prime is 132656502665543. The reversal of 132656502665503 is 305566205656231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132656502665503 - 213 = 132656502657311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132656502665543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 934200722926 + ... + 934200723067.

It is an arithmetic number, because the mean of its divisors is an integer number (33631226027892).

Almost surely, 2132656502665503 is an apocalyptic number.

132656502665503 is a deficient number, since it is larger than the sum of its proper divisors (1868401446065).

132656502665503 is an equidigital number, since it uses as much as digits as its factorization.

132656502665503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1868401446064.

The product of its (nonzero) digits is 29160000, while the sum is 55.

The spelling of 132656502665503 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, five hundred two million, six hundred sixty-five thousand, five hundred three".

Divisors: 1 71 1868401445993 132656502665503