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1328813284147 = 2415513748067
BaseRepresentation
bin10011010101100011011…
…100011001101100110011
311201000220021121221111021
4103111203130121230303
5133232402200043042
62454240504200311
7165001142360266
oct23254334315463
94630807557437
101328813284147
11472601503018
12195648a69097
13983ca6696bb
144845a160cdd
1524873789867
hex13563719b33

1328813284147 has 4 divisors (see below), whose sum is σ = 1334327032456. Its totient is φ = 1323299535840.

The previous prime is 1328813284133. The next prime is 1328813284157. The reversal of 1328813284147 is 7414823188231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1328813284147 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1328813284094 and 1328813284103.

It is not an unprimeable number, because it can be changed into a prime (1328813284157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2756873793 + ... + 2756874274.

It is an arithmetic number, because the mean of its divisors is an integer number (333581758114).

Almost surely, 21328813284147 is an apocalyptic number.

1328813284147 is a deficient number, since it is larger than the sum of its proper divisors (5513748309).

1328813284147 is an equidigital number, since it uses as much as digits as its factorization.

1328813284147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5513748308.

The product of its digits is 2064384, while the sum is 52.

The spelling of 1328813284147 in words is "one trillion, three hundred twenty-eight billion, eight hundred thirteen million, two hundred eighty-four thousand, one hundred forty-seven".

Divisors: 1 241 5513748067 1328813284147