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13299447445 = 52659889489
BaseRepresentation
bin11000110001011010…
…10111011010010101
31021022212020221010121
430120231113122111
5204214124304240
610035405151541
7650400303154
oct143055273225
937285227117
1013299447445
115705211789
1226b1b5b5b1
13133c43813b
1490243759b
1552c8a204a
hex318b57695

13299447445 has 4 divisors (see below), whose sum is σ = 15959336940. Its totient is φ = 10639557952.

The previous prime is 13299447437. The next prime is 13299447451. The reversal of 13299447445 is 54474499231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54474499231 = 371472283763.

It can be written as a sum of positive squares in 2 ways, for example, as 2382123249 + 10917324196 = 48807^2 + 104486^2 .

It is a cyclic number.

It is not a de Polignac number, because 13299447445 - 23 = 13299447437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13299447392 and 13299447401.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1329944740 + ... + 1329944749.

It is an arithmetic number, because the mean of its divisors is an integer number (3989834235).

Almost surely, 213299447445 is an apocalyptic number.

It is an amenable number.

13299447445 is a deficient number, since it is larger than the sum of its proper divisors (2659889495).

13299447445 is an equidigital number, since it uses as much as digits as its factorization.

13299447445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2659889494.

The product of its digits is 4354560, while the sum is 52.

The spelling of 13299447445 in words is "thirteen billion, two hundred ninety-nine million, four hundred forty-seven thousand, four hundred forty-five".

Divisors: 1 5 2659889489 13299447445