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13300030231111 = 131023079248547
BaseRepresentation
bin1100000110001010011110…
…0100111101001001000111
31202002110200222022110022101
43001202213210331021013
53220401430214343421
644141541033412531
72541616101444301
oct301424744751107
952073628273271
1013300030231111
114268569375088
1215a977526a147
13756258b40250
1433da21196971
15180e6e818191
hexc18a793d247

13300030231111 has 4 divisors (see below), whose sum is σ = 14323109479672. Its totient is φ = 12276950982552.

The previous prime is 13300030231087. The next prime is 13300030231121. The reversal of 13300030231111 is 11113203000331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13300030231111 - 25 = 13300030231079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300030231121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511539624261 + ... + 511539624286.

It is an arithmetic number, because the mean of its divisors is an integer number (3580777369918).

Almost surely, 213300030231111 is an apocalyptic number.

13300030231111 is a deficient number, since it is larger than the sum of its proper divisors (1023079248561).

13300030231111 is a wasteful number, since it uses less digits than its factorization.

13300030231111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1023079248560.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13300030231111 its reverse (11113203000331), we get a palindrome (24413233231442).

The spelling of 13300030231111 in words is "thirteen trillion, three hundred billion, thirty million, two hundred thirty-one thousand, one hundred eleven".

Divisors: 1 13 1023079248547 13300030231111