133001011110133 has 4 divisors (see below), whose sum is σ = 133001060352160. Its totient is φ = 133000961868108.

The previous prime is 133001011110119. The next prime is 133001011110181. The reversal of 133001011110133 is 331011110100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133001011110133 - 2⁵ = 133001011110101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133001011110133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133001011810133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20319003 + ... + 26055016.

It is an arithmetic number, because the mean of its divisors is an integer number (33250265088040).

Almost surely, 2^{133001011110133} is an apocalyptic number.

It is an amenable number.

133001011110133 is a deficient number, since it is larger than the sum of its proper divisors (49242027).

133001011110133 is an equidigital number, since it uses as much as digits as its factorization.

133001011110133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49242026.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 133001011110133 its reverse (331011110100331), we get a palindrome (464012121210464).

The spelling of 133001011110133 in words is "one hundred thirty-three trillion, one billion, eleven million, one hundred ten thousand, one hundred thirty-three".