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133001111121 = 344333703707
BaseRepresentation
bin111101111011101111…
…0111110011001010001
3110201022002001111010120
41323313132332121101
54134341241023441
6141033323220453
712415614535314
oct1736736763121
9421262044116
10133001111121
115145072935a
1221939977729
13c707887a28
146619cc097b
1536d6576966
hex1ef77be651

133001111121 has 4 divisors (see below), whose sum is σ = 177334814832. Its totient is φ = 88667407412.

The previous prime is 133001111083. The next prime is 133001111179. The reversal of 133001111121 is 121111100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133001111121 - 26 = 133001111057 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133001111121.

It is not an unprimeable number, because it can be changed into a prime (133001111921) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22166851851 + ... + 22166851856.

It is an arithmetic number, because the mean of its divisors is an integer number (44333703708).

Almost surely, 2133001111121 is an apocalyptic number.

It is an amenable number.

133001111121 is a deficient number, since it is larger than the sum of its proper divisors (44333703711).

133001111121 is an equidigital number, since it uses as much as digits as its factorization.

133001111121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44333703710.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 133001111121 its reverse (121111100331), we get a palindrome (254112211452).

The spelling of 133001111121 in words is "one hundred thirty-three billion, one million, one hundred eleven thousand, one hundred twenty-one".

Divisors: 1 3 44333703707 133001111121