Base | Representation |
---|---|
bin | 111101111011101111… |
… | …0111110011000010001 |
3 | 110201022002001111001012 |
4 | 1323313132332120101 |
5 | 4134341241023212 |
6 | 141033323220305 |
7 | 12415614535163 |
oct | 1736736763021 |
9 | 421262044035 |
10 | 133001111057 |
11 | 51450729301 |
12 | 21939977695 |
13 | c7078879a9 |
14 | 6619cc0933 |
15 | 36d6576922 |
hex | 1ef77be611 |
133001111057 has 2 divisors, whose sum is σ = 133001111058. Its totient is φ = 133001111056.
The previous prime is 133001111041. The next prime is 133001111059. The reversal of 133001111057 is 750111100331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108958747921 + 24042363136 = 330089^2 + 155056^2 .
It is a cyclic number.
It is not a de Polignac number, because 133001111057 - 24 = 133001111041 is a prime.
Together with 133001111059, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133001111059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500555528 + 66500555529.
It is an arithmetic number, because the mean of its divisors is an integer number (66500555529).
Almost surely, 2133001111057 is an apocalyptic number.
It is an amenable number.
133001111057 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001111057 is an equidigital number, since it uses as much as digits as its factorization.
133001111057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 315, while the sum is 23.
Adding to 133001111057 its reverse (750111100331), we get a palindrome (883112211388).
The spelling of 133001111057 in words is "one hundred thirty-three billion, one million, one hundred eleven thousand, fifty-seven".
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