13300112124241 has 4 divisors (see below), whose sum is σ = 13303226179584. Its totient is φ = 13296998068900.

The previous prime is 13300112124239. The next prime is 13300112124251. The reversal of 13300112124241 is 14242121100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13300112124241 - 2¹ = 13300112124239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13300112124251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1557021265 + ... + 1557029806.

It is an arithmetic number, because the mean of its divisors is an integer number (3325806544896).

Almost surely, 2^{13300112124241} is an apocalyptic number.

It is an amenable number.

13300112124241 is a deficient number, since it is larger than the sum of its proper divisors (3114055343).

13300112124241 is an equidigital number, since it uses as much as digits as its factorization.

13300112124241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3114055342.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13300112124241 its reverse (14242121100331), we get a palindrome (27542233224572).

The spelling of 13300112124241 in words is "thirteen trillion, three hundred billion, one hundred twelve million, one hundred twenty-four thousand, two hundred forty-one".