Base | Representation |
---|---|
bin | 11110001111011010111100… |
… | …100101101111111011101001 |
3 | 122102220210010211012111221000 |
4 | 132033122330211233323221 |
5 | 114413042244023101301 |
6 | 1150511512134505213 |
7 | 40005004525644420 |
oct | 3617327445577351 |
9 | 572823124174830 |
10 | 133001121300201 |
11 | 39418505707390 |
12 | 12b00612505209 |
13 | 5929c4b4b2c1b |
14 | 24bb407d7a2b7 |
15 | 10599e747e786 |
hex | 78f6bc96fee9 |
133001121300201 has 32 divisors (see below), whose sum is σ = 245658636748800. Its totient is φ = 69091491583440.
The previous prime is 133001121300191. The next prime is 133001121300221. The reversal of 133001121300201 is 102003121100331.
133001121300201 is a `hidden beast` number, since 1 + 330 + 0 + 1 + 1 + 2 + 130 + 0 + 201 = 666.
It is not a de Polignac number, because 133001121300201 - 214 = 133001121283817 is a prime.
It is a super-2 number, since 2×1330011213002012 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133001121300221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31986799581 + ... + 31986803738.
It is an arithmetic number, because the mean of its divisors is an integer number (7676832398400).
Almost surely, 2133001121300201 is an apocalyptic number.
133001121300201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
133001121300201 is a deficient number, since it is larger than the sum of its proper divisors (112657515448599).
133001121300201 is a wasteful number, since it uses less digits than its factorization.
133001121300201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63973603346 (or 63973603340 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 133001121300201 its reverse (102003121100331), we get a palindrome (235004242400532).
The spelling of 133001121300201 in words is "one hundred thirty-three trillion, one billion, one hundred twenty-one million, three hundred thousand, two hundred one".
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