13300120010213 has 4 divisors (see below), whose sum is σ = 14000126326560. Its totient is φ = 12600113693868.

The previous prime is 13300120010201. The next prime is 13300120010227. The reversal of 13300120010213 is 31201002100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13300120010213 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13300120010191 and 13300120010200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300120030213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350003158145 + ... + 350003158182.

It is an arithmetic number, because the mean of its divisors is an integer number (3500031581640).

Almost surely, 2^{13300120010213} is an apocalyptic number.

It is an amenable number.

13300120010213 is a deficient number, since it is larger than the sum of its proper divisors (700006316347).

13300120010213 is an equidigital number, since it uses as much as digits as its factorization.

13300120010213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700006316346.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13300120010213 its reverse (31201002100331), we get a palindrome (44501122110544).

The spelling of 13300120010213 in words is "thirteen trillion, three hundred billion, one hundred twenty million, ten thousand, two hundred thirteen".