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13300120021103 = 31429036129713
BaseRepresentation
bin1100000110001010110011…
…1011011110100001101111
31202002110221020021021000122
43001202230323132201233
53220402121211133403
644141554002115155
72541621241603556
oct301425473364157
952073836237018
1013300120021103
114268605022693
1215a979b34babb
1375627161a716
1433da2d08ad9d
15180e77652838
hexc18acede86f

13300120021103 has 4 divisors (see below), whose sum is σ = 13729156150848. Its totient is φ = 12871083891360.

The previous prime is 13300120021099. The next prime is 13300120021109. The reversal of 13300120021103 is 30112002100331.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13300120021103 - 22 = 13300120021099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300120021109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214518064826 + ... + 214518064887.

It is an arithmetic number, because the mean of its divisors is an integer number (3432289037712).

Almost surely, 213300120021103 is an apocalyptic number.

13300120021103 is a deficient number, since it is larger than the sum of its proper divisors (429036129745).

13300120021103 is an equidigital number, since it uses as much as digits as its factorization.

13300120021103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 429036129744.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13300120021103 its reverse (30112002100331), we get a palindrome (43412122121434).

The spelling of 13300120021103 in words is "thirteen trillion, three hundred billion, one hundred twenty million, twenty-one thousand, one hundred three".

Divisors: 1 31 429036129713 13300120021103