Base | Representation |
---|---|
bin | 1100000110001010110100… |
… | …0111101100010001000111 |
3 | 1202002110221110021221100112 |
4 | 3001202231013230101013 |
5 | 3220402123021114421 |
6 | 44141554154503235 |
7 | 2541621311041064 |
oct | 301425507542107 |
9 | 52073843257315 |
10 | 13300123223111 |
11 | 426860690a37a |
12 | 15a97a0434b1b |
13 | 75627219bcba |
14 | 33da2d681c6b |
15 | 180e77a8645b |
hex | c18ad1ec447 |
13300123223111 has 4 divisors (see below), whose sum is σ = 13300145616912. Its totient is φ = 13300100829312.
The previous prime is 13300123223089. The next prime is 13300123223117. The reversal of 13300123223111 is 11132232100331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300123223111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13300123223117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10281050 + ... + 11502183.
It is an arithmetic number, because the mean of its divisors is an integer number (3325036404228).
Almost surely, 213300123223111 is an apocalyptic number.
13300123223111 is a deficient number, since it is larger than the sum of its proper divisors (22393801).
13300123223111 is an equidigital number, since it uses as much as digits as its factorization.
13300123223111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22393800.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13300123223111 its reverse (11132232100331), we get a palindrome (24432355323442).
The spelling of 13300123223111 in words is "thirteen trillion, three hundred billion, one hundred twenty-three million, two hundred twenty-three thousand, one hundred eleven".
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