133001462047 has 4 divisors (see below), whose sum is σ = 133557953760. Its totient is φ = 132444970336.

The previous prime is 133001462039. The next prime is 133001462081. The reversal of 133001462047 is 740264100331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133001462047 - 2³ = 133001462039 is a prime.

It is a super-3 number, since 3×133001462047³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133001462017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 278245498 + ... + 278245975.

It is an arithmetic number, because the mean of its divisors is an integer number (33389488440).

Almost surely, 2^133001462047 is an apocalyptic number.

133001462047 is a deficient number, since it is larger than the sum of its proper divisors (556491713).

133001462047 is an equidigital number, since it uses as much as digits as its factorization.

133001462047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 556491712.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 133001462047 its reverse (740264100331), we get a palindrome (873265562378).

The spelling of 133001462047 in words is "one hundred thirty-three billion, one million, four hundred sixty-two thousand, forty-seven".