133002161355541 has 4 divisors (see below), whose sum is σ = 133146886232800. Its totient is φ = 132857436478284.

The previous prime is 133002161355523. The next prime is 133002161355577. The reversal of 133002161355541 is 145553161200331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133002161355541 - 2⁹ = 133002161355029 is a prime.

It is a super-2 number, since 2×133002161355541² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133002161355494 and 133002161355503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133002161356541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72362437251 + ... + 72362439088.

It is an arithmetic number, because the mean of its divisors is an integer number (33286721558200).

Almost surely, 2^{133002161355541} is an apocalyptic number.

It is an amenable number.

133002161355541 is a deficient number, since it is larger than the sum of its proper divisors (144724877259).

133002161355541 is an equidigital number, since it uses as much as digits as its factorization.

133002161355541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144724877258.

The product of its (nonzero) digits is 162000, while the sum is 40.

The spelling of 133002161355541 in words is "one hundred thirty-three trillion, two billion, one hundred sixty-one million, three hundred fifty-five thousand, five hundred forty-one".