13300223321113 has 4 divisors (see below), whose sum is σ = 13300238919888. Its totient is φ = 13300207722340.

The previous prime is 13300223321111. The next prime is 13300223321123. The reversal of 13300223321113 is 31112332200331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13300223321113 - 2¹ = 13300223321111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13300223321111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6441631 + ... + 8251972.

It is an arithmetic number, because the mean of its divisors is an integer number (3325059729972).

Almost surely, 2^{13300223321113} is an apocalyptic number.

It is an amenable number.

13300223321113 is a deficient number, since it is larger than the sum of its proper divisors (15598775).

13300223321113 is an equidigital number, since it uses as much as digits as its factorization.

13300223321113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15598774.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13300223321113 its reverse (31112332200331), we get a palindrome (44412555521444).

The spelling of 13300223321113 in words is "thirteen trillion, three hundred billion, two hundred twenty-three million, three hundred twenty-one thousand, one hundred thirteen".