13300401412433 has 8 divisors (see below), whose sum is σ = 13310169652200. Its totient is φ = 13290636619008.

The previous prime is 13300401412429. The next prime is 13300401412451. The reversal of 13300401412433 is 33421410400331.

It is a happy number.

13300401412433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 208167184 + 13300193245249 = 14428^2 + 3646943^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13300401412433 - 2² = 13300401412429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13300401412396 and 13300401412405.

It is not an unprimeable number, because it can be changed into a prime (13300401462433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6885353 + ... + 8602841.

It is an arithmetic number, because the mean of its divisors is an integer number (1663771206525).

Almost surely, 2^{13300401412433} is an apocalyptic number.

It is an amenable number.

13300401412433 is a deficient number, since it is larger than the sum of its proper divisors (9768239767).

13300401412433 is a wasteful number, since it uses less digits than its factorization.

13300401412433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1723171.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 13300401412433 its reverse (33421410400331), we get a palindrome (46721811812764).

The spelling of 13300401412433 in words is "thirteen trillion, three hundred billion, four hundred one million, four hundred twelve thousand, four hundred thirty-three".