13300420233341 has 4 divisors (see below), whose sum is σ = 13302417600000. Its totient is φ = 13298422866684.

The previous prime is 13300420233293. The next prime is 13300420233383. The reversal of 13300420233341 is 14333202400331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13300420233341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300420238341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 998673341 + ... + 998686658.

It is an arithmetic number, because the mean of its divisors is an integer number (3325604400000).

Almost surely, 2^{13300420233341} is an apocalyptic number.

It is an amenable number.

13300420233341 is a deficient number, since it is larger than the sum of its proper divisors (1997366659).

13300420233341 is an equidigital number, since it uses as much as digits as its factorization.

13300420233341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1997366658.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 13300420233341 its reverse (14333202400331), we get a palindrome (27633622633672).

The spelling of 13300420233341 in words is "thirteen trillion, three hundred billion, four hundred twenty million, two hundred thirty-three thousand, three hundred forty-one".