Base | Representation |
---|---|
bin | 1100000110001100010100… |
… | …0010100010011001000001 |
3 | 1202002111222102102012012221 |
4 | 3001203011002202121001 |
5 | 3220403433234300441 |
6 | 44142102052051041 |
7 | 2541634253044561 |
oct | 301430502423101 |
9 | 52074872365187 |
10 | 13300524525121 |
11 | 42687a2394529 |
12 | 15a9892903a81 |
13 | 756307378102 |
14 | 33da6aaa4da1 |
15 | 180e9ce058d1 |
hex | c18c50a2641 |
13300524525121 has 4 divisors (see below), whose sum is σ = 13300545416112. Its totient is φ = 13300503634132.
The previous prime is 13300524525091. The next prime is 13300524525173. The reversal of 13300524525121 is 12152542500331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13300524525121 - 223 = 13300516136513 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13300524520121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9459475 + ... + 10774168.
It is an arithmetic number, because the mean of its divisors is an integer number (3325136354028).
Almost surely, 213300524525121 is an apocalyptic number.
It is an amenable number.
13300524525121 is a deficient number, since it is larger than the sum of its proper divisors (20890991).
13300524525121 is an equidigital number, since it uses as much as digits as its factorization.
13300524525121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20890990.
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 13300524525121 in words is "thirteen trillion, three hundred billion, five hundred twenty-four million, five hundred twenty-five thousand, one hundred twenty-one".
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