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133010103143 = 274148526123
BaseRepresentation
bin111101111100000000…
…1010001101101100111
3110201022200222022212102
41323320001101231213
54134401041300033
6141034244042315
712416054136161
oct1737001215547
9421280868772
10133010103143
1151455810185
122194099339b
13c7096b5858
14661b181931
1536d7250de8
hex1ef8051b67

133010103143 has 4 divisors (see below), whose sum is σ = 133058632008. Its totient is φ = 132961574280.

The previous prime is 133010103133. The next prime is 133010103197. The reversal of 133010103143 is 341301010331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133010103143 - 28 = 133010102887 is a prime.

It is a super-2 number, since 2×1330101031432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133010103133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24260321 + ... + 24265802.

It is an arithmetic number, because the mean of its divisors is an integer number (33264658002).

Almost surely, 2133010103143 is an apocalyptic number.

133010103143 is a deficient number, since it is larger than the sum of its proper divisors (48528865).

133010103143 is an equidigital number, since it uses as much as digits as its factorization.

133010103143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48528864.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 133010103143 its reverse (341301010331), we get a palindrome (474311113474).

The spelling of 133010103143 in words is "one hundred thirty-three billion, ten million, one hundred three thousand, one hundred forty-three".

Divisors: 1 2741 48526123 133010103143