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13301101000223 = 22136010438771
BaseRepresentation
bin1100000110001110011101…
…1001100111011000011111
31202002120110121011011101122
43001203213121213120133
53220411123324001343
644142235204001155
72541654453024161
oct301434731473037
952076417134348
1013301101000223
114268a68834833
1215a9a139901bb
1375639992803a
1433dac3486931
15180ed3828068
hexc18e766761f

13301101000223 has 4 divisors (see below), whose sum is σ = 13307111441208. Its totient is φ = 13295090559240.

The previous prime is 13301101000219. The next prime is 13301101000237. The reversal of 13301101000223 is 32200010110331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13301101000223 - 22 = 13301101000219 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13301101000123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3005217173 + ... + 3005221598.

It is an arithmetic number, because the mean of its divisors is an integer number (3326777860302).

Almost surely, 213301101000223 is an apocalyptic number.

13301101000223 is a deficient number, since it is larger than the sum of its proper divisors (6010440985).

13301101000223 is an equidigital number, since it uses as much as digits as its factorization.

13301101000223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6010440984.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13301101000223 its reverse (32200010110331), we get a palindrome (45501111110554).

The spelling of 13301101000223 in words is "thirteen trillion, three hundred one billion, one hundred one million, two hundred twenty-three", and thus it is an aban number.

Divisors: 1 2213 6010438771 13301101000223