Base | Representation |
---|---|
bin | 1100000110001110011110… |
… | …0010011011100111000101 |
3 | 1202002120110202111120121010 |
4 | 3001203213202123213011 |
5 | 3220411124421430201 |
6 | 44142235325312433 |
7 | 2541654511461051 |
oct | 301434742334705 |
9 | 52076422446533 |
10 | 13301103311301 |
11 | 4268a6a073113 |
12 | 15a9a14705719 |
13 | 75639a256c40 |
14 | 33dac38c8c61 |
15 | 180ed3b32bd6 |
hex | c18e789b9c5 |
13301103311301 has 16 divisors (see below), whose sum is σ = 19099147866624. Its totient is φ = 8185239605184.
The previous prime is 13301103311257. The next prime is 13301103311303. The reversal of 13301103311301 is 10311330110331.
13301103311301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13301103311301 - 211 = 13301103309253 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13301103311303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5214220 + ... + 7334186.
It is an arithmetic number, because the mean of its divisors is an integer number (1193696741664).
Almost surely, 213301103311301 is an apocalyptic number.
It is an amenable number.
13301103311301 is a deficient number, since it is larger than the sum of its proper divisors (5798044555323).
13301103311301 is a wasteful number, since it uses less digits than its factorization.
13301103311301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2280860.
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 13301103311301 its reverse (10311330110331), we get a palindrome (23612433421632).
The spelling of 13301103311301 in words is "thirteen trillion, three hundred one billion, one hundred three million, three hundred eleven thousand, three hundred one".
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