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133011142002314 = 2211829931395743
BaseRepresentation
bin11110001111100100010001…
…110111101100011010001010
3122102221202000011220221000022
4132033210101313230122022
5114413223304323033224
61150520250341140442
740005511044341402
oct3617442167543212
9572852004827008
10133011142002314
1139421788081184
1212b0254a3ba722
13592ab8756b264
1424bbab8b6b802
151059dd207b65e
hex78f911dec68a

133011142002314 has 8 divisors (see below), whose sum is σ = 199516813545600. Its totient is φ = 66505537487116.

The previous prime is 133011142002307. The next prime is 133011142002317. The reversal of 133011142002314 is 413200241110331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1330111420023143 (a number of 43 digits) contains 333 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (133011142002317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11461274 + ... + 19934469.

It is an arithmetic number, because the mean of its divisors is an integer number (24939601693200).

Almost surely, 2133011142002314 is an apocalyptic number.

133011142002314 is a deficient number, since it is larger than the sum of its proper divisors (66505671543286).

133011142002314 is a wasteful number, since it uses less digits than its factorization.

133011142002314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33514044.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 133011142002314 its reverse (413200241110331), we get a palindrome (546211383112645).

The spelling of 133011142002314 in words is "one hundred thirty-three trillion, eleven billion, one hundred forty-two million, two thousand, three hundred fourteen".

Divisors: 1 2 2118299 4236598 31395743 62791486 66505571001157 133011142002314