Base | Representation |
---|---|
bin | 1100000110001110100010… |
… | …0110011101010110010011 |
3 | 1202002120112000001120202021 |
4 | 3001203220212131112103 |
5 | 3220411144003103321 |
6 | 44142241203432311 |
7 | 2541655116163045 |
oct | 301435046352623 |
9 | 52076460046667 |
10 | 13301121144211 |
11 | 4268a7914325a |
12 | 15a9a1a685697 |
13 | 7563a0b5bb64 |
14 | 33dac600ba95 |
15 | 180ed54a6941 |
hex | c18e899d593 |
13301121144211 has 4 divisors (see below), whose sum is σ = 13461375615912. Its totient is φ = 13140866672512.
The previous prime is 13301121144151. The next prime is 13301121144257. The reversal of 13301121144211 is 11244112110331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13301121144211 - 213 = 13301121136019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13301121844211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80127235726 + ... + 80127235891.
It is an arithmetic number, because the mean of its divisors is an integer number (3365343903978).
Almost surely, 213301121144211 is an apocalyptic number.
13301121144211 is a deficient number, since it is larger than the sum of its proper divisors (160254471701).
13301121144211 is an equidigital number, since it uses as much as digits as its factorization.
13301121144211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 160254471700.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13301121144211 its reverse (11244112110331), we get a palindrome (24545233254542).
The spelling of 13301121144211 in words is "thirteen trillion, three hundred one billion, one hundred twenty-one million, one hundred forty-four thousand, two hundred eleven".
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